CONIKS Prefix Merkle Tree - Is It Necessary to Change Tree-wide Constant for Each Update

As Gary Belvin from Trillian replied:

1. Behavior Tree with interrupted sequence

Firslt remember that a decision tree is not the same as a state machine. You have listed three 'states' but they are not exactly 'states', they are compositions of other actions. Because of this, I will call them 'nodes'.In the 'idle' and 'walk' nodes, make the logic poll for something to flee from after every fixed time period or step. If there is something to flee from, transition the logic to fleeing.Behaviour trees are like compositions of coroutines - they must be cooperative to make sense.If you have not already done so, I recommend reading Chris Simpson's Gamasutra article about behaviour trees.It was an image of his that inspired this answer:Note that all of these nodes are very small, quick, actions/checks. That is a very important principle of behaviour trees - to make sure that all nodes are small, fast actions and that longer running actions are merely the repetition of smaller actions, hence walking can consist of a sequence of moving once and then checking for danger without incurring overhead. If danger has been spotted, the walk 'fails' and some higher up node transitions the AI to 'flee'.

2. Harvest Moon: Tree of Tranquility?

You can only get married once per file. When you have a kid you can make the Journey Rucksack. If you do that you can get married again but you will be starting a new file. So you have to do everything over. Including doing the Rainbows and befriending the characters over again. There are some perks, like keeping the money you had in your original file and the tools start at level three. All the characters are the same. So if you do get married again it will be to one of the normal marriage candidates that you always have to choose from.

3. whats something special about a spider monkey?

They have 8 legs and jump from tree to tree by spinning webs. please do not believe me...i am just kidding. ;-)

4. Harvest moon tree of tranquility?

right this is what you would be able to desire to get married point 2 living house Having finished all the middle activities Having Jin at 8 hearts you in addition to mght would desire to acquire the blue feather (you get it at some point once you walk out of your place a scene will happen the you run to caramel falls) you do no longer choose a double mattress!

5. Colour a binary tree to be a red-black tree

If for each node of a tree, the longest path from it to a leaf node is no more than twice longer than the shortest one, the tree has a red-black coloring.Here's an algorithm to figure out the color of any node nHere n.black-quota is the number of black nodes you expect to see going to a leaf, from node n and n. min-height is the distance to the nearest leaf.For brevity of notation, let $b(n) = $ n.black-quota, $h(n) = $ n.height and $m(n) = $ n.min-height. Theorem: Fix a binary tree $T$. If for every node $n in T$, $h(n) leq 2m(n)$ and for node $r = textroot(T)$, $b(r) in [frac12h(r), m(r)]$ then $T$ has a red-black coloring with exactly $b(r)$ black nodes on every path from root to leaf.Proof: Induction over $b(n)$.Verify that all four trees of height one or two satisfy the theorem with $b(n) = 1$. By definition of red-black tree, root is black. Let $n$ be a node with a black parent $p$ such that $b(p) in [frac12h(p), m(p)]$. Then $b(n) = b(p) -1$, $h(n) = h(p)-1$ and $h(n) geq m(n) geq m(p)-1$. Assume the theorem holds for all trees with root $r$, $b(r)