IMac 2006 Stuck at Grey Screen with Apple and Spinner

I removed the new hard drive and re-installed the original drive. It booted up with no issues. I connected the new drive externally and checked it under Disk Utility. It appears the hd was corrupt and needed repair. I verified the new drive when I originally cloned it so not sure where things went wrong. Anyways I erased and recloned the drive. All is good

1. spinner bait or crankbait for bass?

Crankbaits, they will work better. Use a good color

2. What is this toy called? Metal-Spinner-Thing?

My son had one of those things. Irritated the heck out of me! I wish I could answer your question, but I have no idea either! Still searching... Edit: Chatter rings!

3. Does this prove that Graeme Swann is the most dangerous spinner in the world today.....?

Its a good ad but have you seen Warnie's?

4. Where do u get spinner bait for fishing?

you can get a spinner bait at any bait shop or even *****, walmart almost any store with a sport section (i perfer buzz baits they are like spinner baits but they are like a wheel i have caught 6 pounders on them)

5. has anyone tried spinner bike ?

Yes, they have them at my local healthclub. They are a great workout, much better than the recumbent bikes

6. powder coat paint for painting spinner/spoon blades?

It's really expensive so not worth it

7. What are some reasonably priced, good quality spinner exercise machines?

I've used these bikes for years at my gym and they work and hold up amazingly. They make a cheaper "home" line (as opposed to the "commercial" line) that starts at $499, which I think is incredibly reasonable for such a huge brand bike

8. Sum to infinity of a spinner with 3 colours

It's a variant of the Coupon Collector Problem$G$=there is no green in n spins$B$=there is no blue in n spins$P(Gcup B)=P(G)P(B) - P(Gcap B)$Now:$P(G)=(p_Bp_R)^n$ (only blue and red in n spins)$P(B)=(p_Gp_R)^n$ (only green and red in n spins)$P(Gcap B)=(p_R)^n$ (only red in n spins)and what we want is $1-P(Gcup B)$(the opposite of both green and blue means that either of them is missing)

9. Spinner numbers probability

For this problem, you cannot use the addition rule because the events are not mutually exclusive: that is, it is possible that a sector is shaded AND the number in it is prime. (An example of mutually exclusive events would be, either it is raining or it is not raining, it cannot be both at the same time.) You cannot use the multiplication rule either as the conditions mentioned are not independent; e. g. , the probability of being shaded is different for primes, odd numbers, etc. So, it is better to count them by hand.For part (a), there are 8 sectors which either are shaded or contain a prime number. Thus, the probability of getting one of these is $8/10$. For part (b), there is only one sector which is shaded and contains an even number. Thus, the probability is $1/10$.(Extra: if you really want to use the addition rule, you can add the probability that a sector is shaded to the probability that a sector contains a prime number, and subtract the probability that both conditions occur together. You need to subtract because the case in which both occur is counted once in the first probability, and again in the second. This gives the same answer. If you really want to use the multiplication rule, well, you can not .)

10. Beetle Spin Vs. Spinner...?

If you are going for Bass, go with the normal spinnerbait. The Beetle Spins are smaller and more desinged for smaller fish like Panfish

11. I really need to look cool at school this year. What is the best color for a fidget spinner?

Red seems to be a popular color

12. How do I use an open face spinner reel to fish for trout on a river in Missouri, can i fly fish with this reel?

Spinning reels CAN NOT be used with flies, except, perhaps you used one of those bubble floats and a fly. With spinning reels, you can use small in-line spinners for those trout

13. Best strategy for a game board spinner

I think you can keep the math a little simpler. Yes, there should be a point $m$, above which it is better not to spin again, and below which it is better to spin again.To find $m$, the expected value of the payoff when spinning for a second time should therefore be the same as not spinning for a second time after first spinning $m$. That is, we find should $m$ such that the first spin gives $m$, and the expected total payoff for spinning a second time is also $m$.Now, after first spinning $m$, any number from $1$ to $1000-m$ (and of course there are $1000-m$ such numbers) on the second spin will keep you smaller or equal to $1000$. The expected value of such a 'safe' spin is $frac1001-m2$, and hence the expected total payoff is $m frac1001-m2$On the other hand, any number from $1001-m$ to $1000$ (and there are exactly $m$ such numbers) on the second spin will get you a total of over $1000$, and thus get $0$ total points. So, you have a chance of $frac1000-m1000$ of getting a payoff of $m frac1001-m2$, and a chance of $fracm1000$ of getting a payoff of $0$Thus, the expected payoff spinning a second time is:$$frac1000-m1000 cdot (m frac1001-m2)$$So, set that equal to $m$ (the payoff when not spinning a second time), and now you solve a fairly easy quadratic equation for $m$ to that inflection point, above which it is better not to spin, and below which it is better to spin again. In fact, let's just approximate this number by setting:$$frac1000-m1000 cdot (m frac1000-m2) = m$$That means:$$frac1000-m1000 cdot (frac2m1000-m2) = m$$$$Rightarrow frac1000-m1000 cdot (fracm10002) = m$$$$Rightarrow (1000-m)(m1000) = 2000m$$$$Rightarrow 1,000,000 -m^2= 2000m$$$$Rightarrow m^2 2000m-1,000,000 = 0$$Solve for $m$: $$m=frac-2000sqrt(2000^24,000,000)2=frac-2000sqrt(2000^22000^2)2=frac-20002000sqrt(2)2= (sqrt(2)-1)cdot 1000 approx 414$$Finding precise integer $m$: When $m=414$, the expected payoff is: $frac5861000cdot (414frac15862)=0.586 cdot (414293.5)=0.586 cdot 707.5=414.595$Slightly higher, so yes, spin again!When $m=415$, the expected payoff is: $frac5851000cdot (415frac15852)=0. 585 cdot (415293)=0. 585 cdot 708=414. 18$Slightly lower, so do not spin again!OK, so the strategy is: for any first spin $1$ through $414$: spin again, and for any first spin $415$ through $1000$: do not spin again