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Umm it didnt happen to me...Lakers win 100-96
1. Who want's to join me in banning "The View" on ABC for being too biased?
Absolutely not I can not stand Elizabeth , She thinks she is a know it all & wants her mouth running constantly. & what do you mean say her peace the ***** never shuts up long enough for any of the rest to say what they are trying to say. she tries to over talk every one else , she thinks is the smartest person on the show & she is rude & arrogant, & thinks her opinion is the only one that matters! I would watch it more often if they got rid HER!.
2. What percentile will fetch me an IIM (ABC) call?
Thats tricky.It depends completely on your profile.IIM A- focuses on diversity. For GEM, 99.5 percentile with 90% scores in all of 10th, 12th and Graduation should do the trick.IIM B- focuses on workex. For GEM, 99.1 percentile with 80% scores in all 10th, 12th and graduation, along with work-ex should do.IIM C- focuses more on acads. For GEM, 99.2 percentile with 90% scores in all of 10th, 12th and Graduation should do the trick. Although nothing is certain but for me to comment on that, you need to provide me with your background- 10th, 12th graduation scores and stream. Also work ex (if any) and reservation
3. ABC News Story - TRUE or FALSE: Conservatives give 30% more to charities than liberals?
As Arthur Brooks said, "Who Really Cares?" This talking point has been around since Mitt was giving haircuts in prep school
4. In a triangle ABC, AD is the altitude from A. Given b>c, Angle C = 23 degrees and AD=abc/b^2 - c^2 then angle B?
Results used :Sine law : sin A = fraca2RAnd this trigonometric result :sin^2 A - sin^2 B = (sin A - sin B) * (sin A sin B)Nowsin C = fracADACAnd AD = fracabcb^2-c^2 = frac8R^3sin A sin B sin C4R^2(sin^2B-sin^2C)fracADAC = fracfrac8R^3sin A sin B sin C4R^2(sin^2B-sin^2C)2R sin Bsin C = fracADAC = fracfracsin A sin B sin C(sin^2B-sin^2C)sin Bsin A = (sin^2B-sin^2C)But ABC = pi sin A = sin (pi -B -C)= sin (BC)Now the equation becomes :sin (BC) = (sin^2B-sin^2C)Another result :(sin^2B-sin^2C) = sin (BC)sin (B-C) Hence final obtained equation is :sin (BC) = sin (BC)sin (B-C) sin (BC) = 0 (Not possible )or sin (B-C) = 1Hence B = 113^circ
5. Triangle ABC has vertices of A (4,-1), B(5,6), C(1,3). How can you prove triangle ABC is an isosceles using the distance formula or the Pythagorean theorem?
Treat the sides of the triangle as 2D vectors formed by the difference between their endpoints (the vertices of the triangle).A(4,-1), B(5,6), C(1,3)|A-B| = 1, 7. Length^2 = 17^2|B-C| = 4, 3. Length^2 = 4^23^2|C-A| = 3, 4. Length^2 = 3^24^3BC and AC have the same length, so AB forms the base of an isosceles triangle
6. What does ABC stand for in Roblox Adopt Me?
In Bloxburg, you can see role-players using 'ABC'.For example, 'ABC for a brother or sister.'Or in Adopt Me, 'Looking for Unicorn, ABC to trade!'Hope that answers your question. ^^.
7. ABC is an equilateral triangle. Charges q are placed at each corner. What is the electric intensity at O?
We solve it like this:Let k = 1/4The electric field intensity (E) at O due to A is |E1 |= k (q/r^2) [directed towards midpoint of BC]---(1)And electric field intensity (E) at O due to B is |E2| = k (q/r^2) [directed towards midpoint of AC] ---(2)The electric field intensity (E) at O due to C is |E3| = k (q/r^2) [directed towards midpoint of AB] ---(3)From (1),(2),(3) we get the net electric intensity at O due to A,B,C combined is given by ,E = E1 E2 E3Note that electric field intensity E1,E2,E3 are vector quantities and they form a triad with angle between them = 120, and since they are equal in magnitude they cancel out each otherThus ,net electric intensityE = 0
8. Have you noticed that Fox News is extremely biased for Zimmerman?
It's kinda like how ABC, CBS, NBC, CNN, etc. are all biased towards Martin. There is no one impartial to this. It's not murder though. You call Zimmerman a hot head, yet you have no way to prove that Zimmerman followed Martin with the ill will, spite, or depraved mind to kill him. Up until then, it's self-defense. BTW, if Martin was tackled and pinned, why did not the autopsy find anything showing that? Certainly it would have left a mark on him.