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Many variants of the 79L05 and 7905 need a minimum load, otherwise they produce a too high (absolute value) output voltage. Step one operates the 79L05 completely unloaded, which can cause -8.6V output even on a perfectly working part. If with a 1mA load (5k resistor) the voltage drops to -5V, your chip is OK

I am assembling a metal detector kit of parts. At the end of stage 1 which involves building is 'a simple linear regulator that provides the -5V power supply'. I was getting a test reading of -8.62V and not -5V.

So I have concluded that I should replace the voltage regulator U1 (79L05).

The question is can I replace U1 (79L05) which is -5V 1MA with a MC7905CT which is -5V 1A or is this likely to cause problems elsewhere on the circuit board.

Th only other issue is that the 'legs' on the MC7905CT which is -5V 1A need to be gently filed to allow them through the holes in the board.

Why not simply buy another U1 (79L05)....I am in Morocco and they aren't that easy to find.

I hope this is clear. Thanks in advance.

·OTHER ANSWER:

I am assembling a metal detector kit of parts. At the end of stage 1 which involves building is 'a simple linear regulator that provides the -5V power supply'. I was getting a test reading of -8.62V and not -5V.

So I have concluded that I should replace the voltage regulator U1 (79L05).

The question is can I replace U1 (79L05) which is -5V 1MA with a MC7905CT which is -5V 1A or is this likely to cause problems elsewhere on the circuit board.

Th only other issue is that the 'legs' on the MC7905CT which is -5V 1A need to be gently filed to allow them through the holes in the board.

Why not simply buy another U1 (79L05)....I am in Morocco and they aren't that easy to find.

I hope this is clear. Thanks in advance.

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